include('core/config.php');
include('core/db.php');
include('core/functions.php');

isNotLoggedIn(); //redirect to login page
$userID = $_COOKIE["userID"];

// Query user info from DB
$userQuery = DB::query("SELECT * FROM users WHERE userID = %i", $userID);
foreach($userQuery as $userResult){
$userEmail = $userResult["userEmail"];
$userPermission = $userResult["userPermission"];
}

// Setting permission text
if($userPermission == 1){
$userPermissionText = "Admin";
}else if($userPermission == 0){
$userPermissionText = "User";
}


Any idea why is this error popping up?

I have tried this method:
1) python manage.py makemigrations >>No changes detected
2) python manage.py migrate>>
Operations to perform:
Apply all migrations: admin, auth, contenttypes, menu, sessions
Running migrations:
No migrations to apply.
3) CTRL + SHIFT + R to hard reset http://127.0.0.1:8000/admin/
4) Adding a new menu via http://127.0.0.1:8000/admin/menu/menu/add/

#models.py page
from django.db import models

class Menu(models.Model):
productName = models.CharField(max_length=255)
price = models.FloatField()
image_url = models.CharField(max_length=2083)
category = models.CharField(max_length=255)

def _str_ (self):
return self.product_name


#admin.py page

from django.contrib import admin
from .models import Menu

class MenuAdmin(admin.ModelAdmin):
list_display =('productName', 'price','image_url','category')

admin.site.register(Menu, MenuAdmin)


Whenever an instance of model is created in Django, it displays the object as ModelName Object(1).

How do we make changes to our code so that it changes the display name to its own name?

Hello. For Assignment 1 last question,

Create respective categories pages "/menu/{category_name}" to display all menu items from the database according to their categories
Categories to use:
Starters
Mains
Beverages
Desserts

I have the page up and tested with Http response and I have an idea of using object.filter() to do the separation of item by category.

I have a problem with the code as i tried it multiple way of putting it as below


def Starters(request):
starter = Menu.objects.filters(Menu_menu_category=Starters)
return render(request, 'index.html', {'Menu': starter})


and also


def Starters(request):
starter = Menu.objects.filters(category=Starters)
return render(request, 'index.html', {'Menu': starter})


How do make that function to pick up my data from the table column?

//When i print out the code below, it give ms only 1 result . Not sure why.//

$bikes = array("Honda"=>"exMotion", "Honda"=>"Adv150", "Honda"=>"NC750");

foreach($bikes as $bike => $model) {
echo "$bike = $model
";
}

I am having this problem when I trying to open my Menu page, searched online and they suggested to add "global Menu" after Def. I did it and it works! So now the code is like this.

def index(request):
global Menu
Menu = Menu.objects.all()
return render(request, 'index.html', {'Menu': Menu})



BUT then after i refresh the page it will have another error which is AttributeError at /Menu/
'QuerySet' object has no attribute 'objects'

So everytime i wanted my page to load i have to Ctrl + S my views.py file and the server will reload and then I can see my site for only once!

As titled.

1. Create a new folder “static” in the root of the main project. Same level as the global “templates” directory.

2. Add this code to your base template file (base.html).
{% load staticfiles %}

3. Use this to load the files.

4. Add this to your settings.py file.
STATICFILES_DIRS = [
os.path.join(BASE_DIR, 'static'),
]

Welcome! Use this thread to introduce yourself and have our little community chat here. :)

Do note that you will have to use:
<script type="text/plain" style="display:block;"></script>
to be able to show HTML programming code.

I want to remove the first and last word from a string.
$string = "12121";

I tried trimming it like:
$string = "12121";
$trimmed = trim($string, 1);
print($trimmed);

Result shows 22, but I want 212. Please help.

I'm using Twitter Bootstrap 3, and I have problems when I want to align vertically two div.
Reference: http://jsfiddle.net/corinem/CQstd/

The grid system in Bootstrap uses float: left, not display:inline-block, so the property vertical-align doesn't work. I tried using margin-top to fix it, but I think this is not a good solution for the responsive design.